对Me ^2＋（Me=Ni,Co,Mn）-NH₃-OH--H₂O共沉淀反应体系进行了热力学分析,采用共沉淀法合成了LiNi _1/3 Co _1/3 Mn _1/3 O₂正极材料前驱体Ni _1/3 Co _1/3 Mn _1/3（OH）2,研究了pH值和氨水浓度[N]对前驱体振实密度的影响.热力学分析表明：以氢氧化钠为沉淀剂、氨水为络合剂,采用共沉淀法合成前驱体的最佳pH值为11,最佳[N]为0.1～0.5mol/L;在此条件下,金属阳离子Ni ^2＋、Co ^2＋和Mn ^2＋的损失最小,分别小于1×10 ^-3、1×10 ^-3和1×10 ^-6 mol/L.在pH=11、[N]=0.24mol/L条件下,所合成的前驱体中Ni、Co、Mn的摩尔比为0.324∶0.349∶0.327,与理论设计值1∶1∶1非常接近,其振实密度高达1.32g/cm ³

The thermodynamic analysis of Me ^2＋-NH³-OH_^--H₂O（Me=Ni,Co,Mn） coprecipitation system was carried out,and the precursor Ni _1/3 Co _1/3 Mn _1/3（OH）₂, for cathode material LiNi _1/3 Co _1/3 Mn _1/3 O₂ was synthesized via a coprecipitation method,with NaOH as the precipitant and NH₃·H₂O as the complexing agent.The thermodynamic analysis shows that the optimal conditions are pH value of 11 and ammonia concentration 0.1～0.5mol/L,and the loss of Ni ^2＋,Co ^2＋ and Mn ^2＋ reaches the minimum,that is,1×10 ^-3,1×10 ^-3 and 1×10 ^-6 mol/L,respectively.The molar ratio of Ni/Co/Mn in the synthesized precursor is 0.324∶0.349∶0.327,which approximates the desired 1∶1∶1,and the tap density of the synthesized precursor is up to 1.32g/cm³ when pH value is 11 and an ammonia concentration is 0.24mol/L.